7n^2+50n-48=0

Solution for 7n^2+50n-48=0 equation:

7n^2+50n-48=0

a = 7; b = 50; c = -48;
Δ = b2-4ac
Δ = 502-4·7·(-48)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*7}=\frac{-112}{14}
=-8
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*7}=\frac{12}{14}
=6/7
$